Def of Eigenvalue and Eigenvector:

Let be a n-by-n matrix. A scalar is called an eigenvalue of if there exist a nonzero vector such that

The vector is called an eigenvector of corresponding to the eigenvalue


Theorem(找Eigenvalue的方法):

If is an n-by-n matrix, then is an eigenvalue of if and only if

Proof:

is an eigenvalue of

such that

has nontrivial solutions

is not invertible


Def of eigenspace(所有eigenvector和0向量組成的向量空間):

let be the set of zero vector and all eigenvectors of an n-by-n matrix corresponding the eigenvalue .


Theorem():

The eigenspace of an n-by-n matrix corresponding to the eigenvalue i.e. is a subspace of R^n.

Proof:

Let and is a scalar

(closure)

(closure)

is a subspace of


Def of Matrix similarity:

If and are square matrices of the same size, then we say that is simliar to if there exist an invertible matrix such that

Similar matrices have many properties in common. If and are simliar matrices, then they have the same determinant and eigenvalues.

  1. In general, only property that is shared by all similar matrices is called a similariry invariant or is said to be invariant under similarity.


Def of diagonalizable square matrix:

A square matrix is said to be diagonalizable if there exist an invertible matrix such that is diagonal. In this case, the invertible matrix is said to be diagonalize .


Theorem(判斷方陣是否可對角線化):

If is an n-by-n matrix then is diagonalizable if and only if has n linearly independent eigenvectors.

is diagonalizable

has n linearily independent eigenvectors, say,

where are scalars and need not all distinct.

Let

then


Procedure for diagonalization on n-by-n matrix A:

  1. Find all eigenvelues of .
  2. Find all eigenvectors X of
  3. Number of independent eigenvectors of or No: is not diagonalizable. Yes: let be the linearly independent eigenvectors.
  4. Let then diagonalizes such that

對角線化與可逆之間沒有必然聯繫


Find power of a matrix :

對於可對角線化的矩陣A有:

注意:

即對主軸元素做n次平方


Theorem(存在固有值為0的方陣必不可逆,反之亦然):

A square matrix is singular if and only if is an eigenvalue of A.

Proof:

is an eigenvalue of

A is singular.